A) Mutually exclusive
B) Independent as well as mutually exhaustive
C) Independent
D) Dependent only on A
Correct Answer: A
Solution :
\[P(A\cup B)=\,P(A)+P(B)-P(A\cap B)\] \[\frac{5}{6}=\frac{2}{3}+\frac{1}{2}-P(A\cap B)\] \[\Rightarrow \,P(A\cap \,B)=0\] \ Events A and B are mutually exclusive.You need to login to perform this action.
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