A) 2.68
B) 3.86
C) 4.68
D) 2.86t6
Correct Answer: B
Solution :
\[{{K}_{f}}=\frac{RT_{f}^{2}}{1000\times {{L}_{f}}}\], \[R=8.314J{{K}^{-1}}mo{{l}^{-1}}\] \[\,{{T}_{f}}=273+16.6=289.6K\] ; \[{{L}_{f}}=180.75\,J{{g}^{-1}}\] \[{{K}_{f}}=\frac{8.314\times 289.6\times 289.6}{1000\times 180.75}\]You need to login to perform this action.
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