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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Depression of freezing point of the solvent

  • question_answer
    The  amount of urea to be dissolved in 500 ml of water (K =18.6 K \[mol{{e}^{-1}}\]in 100g solvent)  to produce  a  depression of \[{{0.186}^{o}}C\] in  freezing point  is          [MH CET 2000]

    A)                 9 g 

    B)                 6 g

    C)                 3 g          

    D)                 0.3 g

    Correct Answer: C

    Solution :

             \[\Delta {{T}_{f}}=\frac{100\times K\times w}{m\times W}\]   \[\therefore \,0.186=\frac{100\times 18.6\times w}{60\times 500}\]                 \[w=3g\]


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