A) \[\pm \,2\]
B) \[\pm \frac{1}{2}\]
C) \[\pm \frac{\sqrt{3}}{2}\]
D) \[\pm \frac{2}{\sqrt{3}}\]
Correct Answer: A
Solution :
Given \[f(x)={{\left( \sqrt{x}+\frac{1}{\sqrt{x}} \right)}^{2}}\] \[f(x)=x+\frac{1}{x}+2\] and \[f'(x)=3/4\] So, \[1-\frac{1}{{{x}^{2}}}=\frac{3}{4}\] Þ \[\frac{1}{{{x}^{2}}}=\frac{1}{4}\] Þ \[x=+2,\,-2\].You need to login to perform this action.
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