A) ? 2
B) 0
C) 2
D) 4
Correct Answer: B
Solution :
\[f(x)=|x-1|+|x-5|\] \[f(x)=\left\{ \begin{align} & -(x-1)-(x-5),\,\,\,x<1 \\ & \,\,\,\,(x-1)-(x-5),\,\,\,1<x<5 \\ & \,\,\,\,\,\,\,x-1+x-5,\,\,\,\,x>5 \\ \end{align} \right.\] \[f(x)=\left\{ \begin{matrix} 6-2x, & x<1 \\ 4\,\,\,\,\,\,, & 1<x<5 \\ 2x-6, & x>5 \\ \end{matrix} \right.\] \[\because \] \[x=3\in (1,\,5)\], \ For x = 3, \[f(x)=4,\ \ f'(x)=0\].You need to login to perform this action.
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