A) \[{{\tan }^{-1}}x\]
B) \[2x{{\tan }^{-1}}x\]
C) \[2x{{\tan }^{-1}}x-1\]
D) \[\frac{2x}{{{\tan }^{-1}}x}\]
Correct Answer: B
Solution :
\[y=(1+{{x}^{2}}){{\tan }^{-1}}x-x\] Þ \[\frac{dy}{dx}=(1+{{x}^{2}}).\frac{1}{(1+{{x}^{2}})}+{{\tan }^{-1}}x(2x)-1=2x{{\tan }^{-1}}x.\]You need to login to perform this action.
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