A) \[\frac{2x}{1+{{x}^{4}}}\]
B) \[\frac{2x}{\sqrt{1+4x}}\]
C) \[\frac{-2x}{1+{{x}^{4}}}\]
D) \[\frac{-2x}{\sqrt{1+{{x}^{2}}}}\]
Correct Answer: C
Solution :
\[y={{\cot }^{-1}}\left( {{x}^{2}} \right)\] \[\frac{dy}{dx}=\frac{-1}{1+{{({{x}^{2}})}^{2}}}\frac{d}{dx}({{x}^{2}})=\frac{-1}{1+{{x}^{4}}}(2x)=\frac{-2x}{1+{{x}^{4}}}\].You need to login to perform this action.
You will be redirected in
3 sec