A) ½
B) 2
C) 2m/n
D) m/ 2n
Correct Answer: B
Solution :
\[{{x}^{m}}{{y}^{n}}={{(x+y)}^{m+n}}\] \[{{x}^{m}}.(n{{y}^{n-1}}).\frac{dy}{dx}+{{y}^{n}}(m{{x}^{m-1}})=(m+n)\,{{(x+y)}^{m+n-1}}\]\[\left( 1+\frac{dy}{dx} \right)\] After solving, we find \[\frac{dy}{dx}=\frac{y}{x}\] and \[{{\left. \frac{dy}{dx} \right|}_{x=1,\,y=2}}=\frac{2}{1}=2\].You need to login to perform this action.
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