A) \[x{{\tan }^{-1}}x\]
B) \[2{{\tan }^{-1}}x\]
C) \[2x{{\tan }^{-1}}x+1\]
D) \[x{{\tan }^{-1}}x+1\]
Correct Answer: C
Solution :
\[\frac{d}{dx}[(1+{{x}^{2}}){{\tan }^{-1}}x]=1+2x{{\tan }^{-1}}x\].You need to login to perform this action.
You will be redirected in
3 sec