A) \[2\tan 2x\sec 2x\]
B) \[\tan 2x\sec 2x\]
C) \[-\tan 2x\sec 2x\]
D) \[-2\tan 2x\sec 2x\]
Correct Answer: D
Solution :
\[y=\frac{\tan x+\cot x}{\tan x-\cot x}=-\frac{1+{{\tan }^{2}}x}{1-{{\tan }^{2}}x}=-\sec 2x\] \[\Rightarrow \frac{dy}{dx}=-2\sec 2x\tan 2x\].You need to login to perform this action.
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