A) \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
B) \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
C) \[-\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
D) \[-\frac{a}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
Correct Answer: A
Solution :
\[y={{\tan }^{-1}}\left( \frac{{{x}^{1/3}}+{{a}^{1/3}}}{1-{{x}^{1/3}}.{{a}^{1/3}}} \right)={{\tan }^{-1}}({{x}^{1/3}})+{{\tan }^{-1}}{{a}^{1/3}}\] Þ \[\frac{dy}{dx}=\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\].You need to login to perform this action.
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