A) \[x\,{{e}^{x}}(2\sin x+x\sin x+x\cos x)\]
B) \[x\,{{e}^{x}}(2\sin x+x\sin x-\cos x)\]
C) \[x\,{{e}^{x}}(2\sin x+x\sin x+\cos x)\]
D) None of these
Correct Answer: A
Solution :
\[\frac{d}{dx}\left( {{x}^{2}}{{e}^{x}}\sin x \right)={{x}^{2}}\frac{d}{dx}\left( {{e}^{x}}\sin x \right)\]\[+{{e}^{x}}\sin x\frac{d}{dx}({{x}^{2}})\] \[=x{{e}^{x}}(2\sin x+x\sin x+x\cos x)\].You need to login to perform this action.
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