A) \[\frac{1}{2(1+\cos x)}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{4}\]
D) None of these
Correct Answer: B
Solution :
\[f(x)={{\tan }^{-1}}\left( \frac{\sin x}{1+\cos x} \right)={{\tan }^{-1}}\left[ \tan \frac{x}{2} \right]=\frac{x}{2}\] Þ \[f'(x)=\frac{1}{2}.\] Hence \[f'\left( \frac{\pi }{3} \right)=\frac{1}{2}\].You need to login to perform this action.
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