A) \[-2x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
B) \[-4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
C) \[4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
D) \[-2(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
Correct Answer: C
Solution :
\[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]=-\sin {{(1-{{x}^{2}})}^{2}}\frac{d}{dx}{{(1-{{x}^{2}})}^{2}}\] \[=4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\].You need to login to perform this action.
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