A) \[\frac{3}{\sqrt{1-{{x}^{2}}}}\]
B) \[\frac{-3}{\sqrt{1-{{x}^{2}}}}\]
C) \[\frac{1}{\sqrt{1-{{x}^{2}}}}\]
D) \[\frac{-1}{\sqrt{1-{{x}^{2}}}}\]
Correct Answer: A
Solution :
Put \[x=\sin \theta ,\] we get \[\frac{d}{dx}{{\sin }^{-1}}(3x-4{{x}^{3}})\] \[=\frac{d}{dx}{{\sin }^{-1}}(\sin 3\theta )=\frac{3}{\sqrt{1-{{x}^{2}}}}\].You need to login to perform this action.
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