A) 0
B) 1
C) ? 1
D) None of these
Correct Answer: A
Solution :
\[y={{\sin }^{-1}}\left( \frac{19}{20}x \right)+{{\cos }^{-1}}\left( \frac{19}{20}x \right)=\frac{\pi }{2}\] Þ \[\frac{dy}{dx}=0\], \[\left( \because {{\sin }^{-1}}x+{{\cos }^{-1}}x=\frac{\pi }{2} \right)\].You need to login to perform this action.
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