A) 0
B) \[{{x}_{0}}\]
C) \[g({{x}_{0}})\]
D) None of these
Correct Answer: C
Solution :
\[f'({{x}_{0}})=\underset{x\to {{x}_{0}}}{\mathop{\lim }}\,\frac{(x-{{x}_{0}})g(x)-0}{x-{{x}_{0}}}=\underset{x\to {{x}_{0}}}{\mathop{\lim }}\,g(x)=g({{x}_{0}})\] Since g is continuous.You need to login to perform this action.
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