A) \[-\frac{1}{2\sqrt{x}}\]
B) ? 2
C) \[-\frac{1}{{{x}^{2}}\sqrt{x}}\]
D) 0
Correct Answer: D
Solution :
\[f(x)={{\log }_{\sqrt{x}}}\left( \frac{1}{x} \right)=\frac{\log \left( \frac{1}{x} \right)}{\log \sqrt{x}}=\frac{(-1)\log x}{(1/2)\,\log x}=-2\] Þ \[{f}'(x)=0\].You need to login to perform this action.
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