A) \[\tan x\,+x\,\,{{\sec }^{2}}x\]
B) \[\ln \,10\,(\tan x+x{{\sec }^{2}}x)\]
C) \[\ln \,10\,\left( \tan x+\frac{x}{{{\cos }^{2}}x}+\tan x\sec x \right)\]
D) \[x\tan x\,\text{ln}\,\,10\]
Correct Answer: B
Solution :
\[{{10}^{-x\tan x}}\frac{d}{dx}({{10}^{x\tan x}})\] = \[{{10}^{-x\tan x}}{{.10}^{x\tan x}}.\log 10(\tan x+x{{\sec }^{2}}x)\] = \[\log 10(\tan x+x{{\sec }^{2}}x)\].You need to login to perform this action.
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