A) 1 : 2
B) 1 : 1
C) 3 : 1
D) 2 : 1
Correct Answer: D
Solution :
\[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}+{{l}_{2}}}{{{l}_{1}}-{{l}_{2}}}=\frac{(6+2)}{(6-2)}=\frac{2}{1}\]You need to login to perform this action.
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