A) \[0.18\,\Omega \]
B) \[0.0018\,\Omega \]
C) \[0.002\,\Omega \]
D) \[0.12\,\Omega \]
Correct Answer: C
Solution :
\[S=\frac{{{i}_{g}}G}{(i-{{i}_{g}})}\]\[=\frac{1\times 0.018}{10-1}=\frac{0.018}{9}=0.002\Omega \]You need to login to perform this action.
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