A) 0.005 V/cm
B) 0.05 V/cm
C) 0.02 V/cm
D) 0.2 V/cm
Correct Answer: A
Solution :
Potential gradient \[=\frac{e}{(R+{{R}_{h}}+r)}.\frac{R}{L}\] \[=\frac{2}{(15+5+0)}\times \frac{5}{1}\]\[=0.5\frac{V}{m}=0.005\,\frac{V}{cm}\]You need to login to perform this action.
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