A) \[5\times {{10}^{-5}}\,V/mm\]
B) \[2.5\times {{10}^{-4}}\,V/cm\]
C) \[0.62\times {{10}^{-4}}\,V/mm\]
D) \[1\times {{10}^{-5}}\,V/mm\]
Correct Answer: A
Solution :
Potential gradient \[x=\frac{e}{(R+{{R}_{h}}+r)}\cdot \frac{R}{L}\] Þ \[x=\frac{2.5}{(20+80+0)}\times \frac{20}{10}=5\times {{10}^{-5}}\frac{V}{mm}\]You need to login to perform this action.
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