A) \[210\,k\Omega \]
B) \[315\,k\Omega \]
C) \[420\,k\Omega \]
D) \[440\,k\Omega \]
Correct Answer: C
Solution :
Here \[i=\frac{110}{20\times {{10}^{3}}+R}\] \[\because \] \[V=iR\] Þ \[5=\left( \frac{110}{20\times {{10}^{3}}+R} \right)\times 20\times {{10}^{3}}\] Þ \[{{10}^{5}}+5R=22\times {{10}^{5}}\]Þ \[R=21\times \frac{{{10}^{5}}}{5}=420\,K\Omega \]You need to login to perform this action.
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