A) \[{{10}^{-2}}\,volt/m\]
B) \[{{10}^{-1}}\,volt/m\]
C) \[3.2\times {{10}^{-2}}\,volt/m\]
D) \[1\,volt/m\]
Correct Answer: A
Solution :
Potential gradient\[=\frac{V}{L}=\frac{iR}{L}=\frac{i\rho L}{AL}=\frac{i\rho }{A}\] \[=\frac{0.2\times 40\times {{10}^{-8}}}{8\times {{10}^{-6}}}={{10}^{-2}}\,V/m\]You need to login to perform this action.
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