A) 30 mV/cm
B) 10 mV/cm
C) 20 mV/cm
D) 4 mV/cm
Correct Answer: B
Solution :
Potential gradient = \[\frac{e.R}{(R+r).L}\]= \[\frac{10\times 3}{(3+3)\times 5}\]. \[=1V/m=10\,mV/cm.\]You need to login to perform this action.
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