A) 1 ohm
B) 2 ohm
C) 3 ohm
D) 4 ohm
Correct Answer: A
Solution :
\[i=\frac{V}{R}\Rightarrow \,2=\frac{6}{\frac{6\times 3}{6+3}+R}=\frac{6}{2+R}\]Þ \[R=1\,\,\Omega \].You need to login to perform this action.
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