A) 20000 W
B) 19989 W
C) 10000 W
D) 9989 W
Correct Answer: B
Solution :
\[V=i.R\text{. }=\frac{e}{(R+{{R}_{h}}+r)}\,.\,R\Rightarrow {{10}^{-3}}=\frac{2}{(10+R+r)}\times 10\] \[\Rightarrow R=19,989\Omega \].You need to login to perform this action.
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