A) 0
B) 1
C) 2
D) 3
Correct Answer: B
Solution :
Let \[x<0\Rightarrow |x|=-x\] Þ \[f(x)=\frac{d}{dx}\left( \frac{x}{1-x} \right)=\frac{1}{{{(1-x)}^{2}}}\] Þ \[{{[{f}'(x)]}_{x=0}}=1\] . Again \[x>0\] Þ \[|x|\,=\,x\] \[f(x)=\frac{d}{dx}\left( \frac{x}{1+x} \right)=\frac{1}{{{(1+x)}^{2}}}\Rightarrow {{[{f}'(x)]}_{x=0}}=1\] Þ \[{f}'(0)=1\] .You need to login to perform this action.
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