A) 5
B) 6
C) 3
D) 4
Correct Answer: A
Solution :
\[f'(1)=\underset{h\to 0}{\mathop{\lim }}\,\frac{f(1+h)-f(1)}{h};\] As function is differentiable so it is continous as it is given that \[\underset{h\to 0}{\mathop{\lim }}\,\frac{f(1+h)}{h}=5\] and hence \[f(1)=0\] . Hence \[f'(1)=\underset{h\to 0}{\mathop{\lim }}\,\frac{f(1+h)}{h}=5\] .
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