A) \[f(x)g(0)\]
B) \[3g(0)\]
C) \[f(x)\cos 3x\]
D) \[3f(x)g(0)\]
E) \[3f(x)g(x)\]
Correct Answer: C
Solution :
\[f(x)=1+\sin (3x)g(x)\] \[f'(x)=3\cos 3x\,g(x)+\sin 3x\,g'(x)\]\[=f(x)\cos 3x\].You need to login to perform this action.
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