A) 0
B) 1
C) 2
D) 3
Correct Answer: D
Solution :
\[f(x)={{x}^{2}}-2x+4\]; \[f'(x)=2x-2\] At \[x=c\], \[f'(c)=2c-2\] \[f(5)={{5}^{2}}-2(5)+4=19\]; \[f(1)={{1}^{2}}-2(1)+4=3\] \[\frac{f(5)-f(1)}{5-1}=f(c)\] Þ \[\frac{19-3}{5-1}=2c-2\] Þ \[\frac{16}{4}=2c-2\] Þ \[4=2c-2\] Þ \[2c=6\] or \[c=3\].You need to login to perform this action.
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