JEE Main & Advanced Mathematics Differentiation Question Bank Differentiation by Substitution

  • question_answer
    If \[y={{a}_{0}}+{{a}_{1}}x+{{a}_{2}}{{x}^{2}}+.....+{{a}_{n}}{{x}^{n}},\]then \[{{y}_{n}}=\]

    A)            \[n!\]

    B)            \[n!{{a}_{n}}x\]

    C)            \[n!{{a}_{n}}\]

    D)            None of these

    Correct Answer: C

    Solution :

               \[=2\frac{{{a}^{2}}}{2}\sin (\pi -2\theta )+\frac{1}{2}{{a}^{2}}\sin 4\theta \]            \[{{y}_{1}}={{a}_{1}}+2{{a}_{2}}x+......+n{{a}_{n}}{{x}^{n-1}}\]            \[{{y}_{2}}=2{{a}_{2}}+6{{a}_{3}}x+......+n(n-1){{a}_{n}}{{x}^{n-2}}\]            ......................................            ......................................            \[{{y}_{n}}=n!{{a}_{n}}\].


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