A) \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=2xy\]
B) \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}=\frac{dy}{dx}\]
C) \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}-\frac{dy}{dx}+y=0\]
D) \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}=2xy\]
Correct Answer: B
Solution :
\[\frac{dy}{dx}=2bx,\ \ \frac{{{d}^{2}}y}{d{{x}^{2}}}=2b\]Þ \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}=2bx=\frac{dy}{dx}\].
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