A) \[y\]
B) \[y'\]
C) 0
D) \[y''\]
Correct Answer: B
Solution :
\[y=a{{e}^{x}}+b{{e}^{-x}}+c\] Þ \[{y}'=a{{e}^{x}}-b{{e}^{-x}}\] Þ \[{{y}'}'=a{{e}^{x}}+b{{e}^{-x}}\] Þ\[{{{y}'}'}'=a{{e}^{x}}-b{{e}^{-x}}={y}'\].You need to login to perform this action.
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