A) \[{{\tan }^{2}}x\]
B) \[\tan x\]
C) \[-\tan x\]
D) None of these
Correct Answer: D
Solution :
Let \[y={{\sin }^{2}}x\] and \[z={{\cos }^{2}}x\] Þ \[\frac{dy}{dx}=\sin 2x\] and \[\frac{dz}{dx}=-\sin 2x\], \ \[\frac{dy}{dz}=-1\].You need to login to perform this action.
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