A) \[\frac{y+2\sin x}{2\sin y+x}\]
B) \[\frac{y+\sin 2x}{2\sin y-x}\]
C) \[\frac{y+2\sin x}{\sin y+x}\]
D) None of these
Correct Answer: B
Solution :
\[{{\sin }^{2}}x+2\cos y+xy=0\] \[\Rightarrow 2\sin x\cos x-2\sin y\frac{dy}{dx}+y+x\frac{dy}{dx}=0\] \[\therefore \frac{dy}{dx}=\frac{y+\sin 2x}{2\sin y-x}\].You need to login to perform this action.
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