A) \[\frac{b\tan \theta }{a}\]
B) \[\frac{a\tan \theta }{b}\]
C) \[\frac{a}{b\tan \theta }\]
D) \[\frac{b}{a\tan \theta }\]
Correct Answer: A
Solution :
\[x=a\left( \sin 2\theta +\frac{1}{2}\sin 4\theta \right)\], \[y=b\left( \cos 2\theta -\frac{1}{2}(1+\cos 4\theta ) \right)\] \[\therefore \frac{dx}{d\theta }=2a(\cos 2\theta +\cos 4\theta )=2a.2\cos 3\theta \cos \theta \] and \[\frac{dy}{d\theta }=2b(\sin 4\theta -\sin 2\theta )=2b.2\cos 3\theta \sin \theta \] \[\therefore \frac{dy}{dx}=\frac{dy}{d\theta }\div \frac{dx}{d\theta }=\frac{b}{a}\tan \theta \].
You need to login to perform this action.
You will be redirected in
3 sec
