JEE Main & Advanced Mathematics Differentiation Question Bank Differentiation of implicit function Parametric

  • question_answer
    If \[{{x}^{2}}{{e}^{y}}+2xy{{e}^{x}}+13=0\], then dy/dx =            [RPET 1987]

    A)            \[\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]

    B)            \[\frac{2x{{e}^{x-y}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]

    C)            \[-\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]

    D)            None of these

    Correct Answer: C

    Solution :

               \[\frac{dy}{dx}=-\frac{\partial f/\partial x}{\partial f/\partial y}=-\frac{2x{{e}^{y}}+2xy{{e}^{x}}+2y{{e}^{x}}}{{{x}^{2}}{{e}^{y}}+2x{{e}^{x}}}\]                       \[=-\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\], [Dividing \[{{N}^{r}}\]and\[{{D}^{r}}\]by \[{{e}^{x}}\]].


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