A) \[\cos \theta \]
B) \[\tan \theta \]
C) \[\sec \theta \]
D) cosecq
Correct Answer: B
Solution :
\[\frac{dy}{dx}=\frac{dy/d\theta }{dx/d\theta }\]=\[\frac{a[\cos \theta -\theta (-\sin \theta )-\cos \theta ]}{a[-\sin \theta +\theta \cos \theta +\sin \theta ]}\] = \[\frac{\theta \sin \theta }{\theta \cos \theta }=\tan \theta \].
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