A) \[(y-2x)\frac{dy}{dx}+3x-2y=0\]
B) \[y\frac{dy}{dx}+x-2y=0\]
C) \[a\text{ }\left( y\frac{dy}{dx}+x-2y \right)=0\]
D) None of these
Correct Answer: B
Solution :
Taking \[\log \], we get \[\log (x-y)+\frac{x}{x-y}=\log k\] Þ \[(x-y)-(x-y)\frac{dy}{dx}+(x-y)-x+\frac{dy}{dx}=0\] Þ \[y\frac{dy}{dx}+x=2y\].
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