JEE Main & Advanced Mathematics Differentiation Question Bank Differentiation of implicit function Parametric

  • question_answer
    If \[y=\sqrt{\frac{(x-a)(x-b)}{(x-c)(x-d)}}\], then \[\frac{dy}{dx}=\]

    A)            \[\frac{y}{2}\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]

    B)            \[y\,\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]

    C)            \[\frac{1}{2}\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]

    D)            None of these

    Correct Answer: A

    Solution :

               \[y=\sqrt{\left[ \frac{(x-a)(x-b)}{(x-c)(x-d)} \right]}\]   Þ\[\log y=\frac{1}{2}[\log (x-a)+\log (x-b)-\log (x-c)-\log (x-d)]\]            Differentiating w.r.t. x we get            \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{2}\left[ \frac{1}{(x-a)}+\frac{1}{(x-b)}-\frac{1}{(x-c)}-\frac{1}{(x-d)} \right]\]            Thus \[\frac{dy}{dx}=\frac{y}{2}\left[ \frac{1}{(x-a)}+\frac{1}{(x-b)}-\frac{1}{(x-c)}-\frac{1}{(x-d)} \right]\].


You need to login to perform this action.
You will be redirected in 3 sec spinner