JEE Main & Advanced Mathematics Differentiation Question Bank Differentiation of implicit function Parametric

  • question_answer
    If \[y={{x}^{\sqrt{x}}},\]then \[\frac{dy}{dx}\]=

    A)            \[{{x}^{\sqrt{x}}}\frac{2+\log x}{2\sqrt{x}}\]

    B)            \[{{x}^{\sqrt{x}}}\frac{2+\log x}{\sqrt{x}}\]

    C)            \[\frac{2+\log x}{2\sqrt{x}}\]

    D)            None of these

    Correct Answer: A

    Solution :

               \[y={{x}^{\sqrt{x}}}\Rightarrow {{\log }_{e}}y=\sqrt{x}\log x\]                    Þ \[\frac{1}{y}\frac{dy}{dx}=\sqrt{x}\frac{1}{x}+\frac{1}{2\sqrt{x}}\log x\] or \[\frac{dy}{dx}={{x}^{\sqrt{x}}}\left[ \frac{2+{{\log }_{e}}x}{2\sqrt{x}} \right]\]


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