JEE Main & Advanced Mathematics Differentiation Question Bank Differentiation of implicit function Parametric

  • question_answer
    If \[y={{x}^{2}}+{{x}^{\log x}},\]then \[\frac{dy}{dx}=\]                                 [DSSE 1986]

    A)            \[\frac{{{x}^{2}}+\log x.{{x}^{\log x}}}{x}\]

    B)            \[{{x}^{2}}+\log x.{{x}^{\log x}}\]

    C)            \[\frac{2({{x}^{2}}+\log x.{{x}^{\log x}})}{x}\]

    D)            None of these

    Correct Answer: C

    Solution :

               \[y={{x}^{2}}+{{x}^{\log x}}\]Þ \[\frac{dy}{dx}=2x+{{x}^{\log x}}\left( 2{{\log }_{e}}x.\frac{1}{x} \right)\]                      \[=\frac{2({{x}^{2}}+{{x}^{\log x}}{{\log }_{e}}x)}{x}\].


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