A) An OR gate and an AND gate respectively
B) An AND gate and a NOT gate respectively
C) An AND gate and an OR gate respectively
D) An OR gate and a NOT gate respectively.
Correct Answer: A
Solution :
\[C=\overline{\bar{A}.\bar{B}}=\overline{\bar{A}+\bar{B}}=A+B\] (De morgan?s theorem) Hence output C is equivalent to OR gate. \[C=\overline{\overline{AB}.\overline{AB}}=\overline{\overline{AB}+\overline{AB}}=AB+AB=AB\] In this case output C is equivalent to AND gate.You need to login to perform this action.
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