A) 0, 0
B) 0, 1
C) 1, 0
D) 1, 1
Correct Answer: A
Solution :
The given Boolean expression can be written as \[Y=(\overline{A+B}).(\overline{A.B})=(\bar{A}.\bar{B}).(\bar{A}+\bar{B})=(\bar{A}\,\bar{A}).\bar{B}+\bar{A}(\bar{B}.\bar{B})\] \[=\bar{A}.\bar{B}+\bar{A}\,\bar{B}=\bar{A}\,\bar{B}\]A | B | Y |
0 | 0 | 1 |
1 | 0 | 0 |
0 | 1 | 0 |
1 | 1 | 0 |
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