A) \[A=0,\,\,B=1,\,\,C=0\]
B) \[A=1,\,\,B=0,\,\,C=0\]
C) \[A=1,\,\,B=0,\,\,C=1\]
D) \[A=1,\,\,B=1,\,\,C=0\]
Correct Answer: C
Solution :
The Boolean expression for the given combination is output \[Y=(A+B).C\] The truth table isA | B | C | Y =(A+B).C |
0 | 0 | 0 | 0 |
1 | 0 | 0 | 0 |
0 | 1 | 0 | 0 |
0 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 1 | 1 |
1 | 1 | 1 | 1 |
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