2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Semiconducting Devices

JEE Main & Advanced Physics Semiconducting Devices Question Bank Digital Electronics

  • question_answer
    The truth table shown in figure is for                 [Pb. CET 1998]            A   0     0     1     1            B   0     1     0     1            Y   1     0     0     1

    A)            XOR                                         

    B)            AND

    C)            XNOR                                      

    D)            OR

    Correct Answer: C

    Solution :

                       For ?XNOR? gate \[Y=\bar{A}\,\bar{B}+AB\]      i.e. \[\bar{0}.\bar{0}+0.0=1.1+0.0=1+0=1\] \[\bar{0}.\bar{1}+0.1=1.0+0.1=0+0=0\] \[\bar{1}.\bar{0}+1.0=0.1+1.0=0+0=0\] \[\bar{1}.\bar{1}+1.1=0.0+1.1=0+1=1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner