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NEET Physics Mathematical Tools, Units & Dimensions Question Bank Dimensions

  • question_answer
    According to Newton, the viscous force acting between liquid layers of area A and velocity gradient \[\Delta v/\Delta z\] is given by \[F=-\eta A\frac{\Delta v}{\Delta z}\] where \[\eta \] is constant called coefficient of viscosity. The dimension of \[\eta \] are?                                                                                [JIPMER 2001, 02]

    A)             \[[M{{L}^{2}}{{T}^{-2}}]\]        

    B)             \[[M{{L}^{-1}}{{T}^{-1}}]\]

    C)             \[[M{{L}^{-2}}{{T}^{-2}}]\]       

    D)             \[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]

    Correct Answer: B

    Solution :

                    \[F=-\eta A\frac{\Delta v}{\Delta z}\Rightarrow [\eta ]=[M{{L}^{-1}}{{T}^{-1}}]\]             As \[F=[ML{{T}^{-2}}],\,\,A=[{{L}^{2}}],\,\frac{\Delta v}{\Delta z}=[{{T}^{-1}}]\]


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