A) \[m=1\], \[n=1\]
B) \[m=1,\ n=2\]
C) \[m=2,\ n=1\]
D) \[m=2,\ n=2\]
Correct Answer: B
Solution :
As \[x=K{{a}^{m}}\times {{t}^{n}}\] \[\left[ {{M}^{0}}L{{T}^{0}} \right]={{\left[ L{{T}^{-2}} \right]}^{m}}{{\left[ T \right]}^{n}}=\left[ {{L}^{m}}{{T}^{-2m+n}} \right]\] \[\therefore \] \[m=1\] and \[-2m+n=0\]Þ \[n=2\].You need to login to perform this action.
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